Mentors – KLEE, CUSAT, PSC Law coaching Law Entrance Coaching Centre, Ernakulam +91 81290 48880Call
Home › KLEE Previous Papers › KLEE 2026 5-Year LLB › Arithmetic & Mental Ability

Arithmetic & Mental Ability – KLEE 2026 5-Year LLB

Click an option to check your answer, or click View Answer. Exam held on 28 June 2026 · Paper code 17/2026/OL.

64.

If a given number is increased by 25% , the number becomes 320. The given number is

  1. A. 286
  2. B. 264
  3. C. 276
  4. D. 256

Answer: Option D

Explanation:

x × 1.25 = 320 → x = 320 ÷ 1.25 = 256.

65.

If an item is sold for Rs.540 at a loss of 10%, then the cost price of the item is

  1. A. Rs.630.
  2. B. Rs.610.
  3. C. Rs.600.
  4. D. Rs.620.

Answer: Option C

Explanation:

Sold at 10% loss, so SP = 0.9 × CP. 0.9 × CP = 540 → CP = Rs. 600.

66.

A can complete a work in 15 days and B can complete the same work in 45 days . Together, they can complete the same work in

  1. A. 12.25 days
  2. B. 11.5 days
  3. C. 12.5 days
  4. D. 11.25 days

Answer: Option D

Explanation:

Work per day = 1/15 + 1/45 = 3/45 + 1/45 = 4/45. Time = 45/4 = 11.25 days.

67.

The arithmetic mean of 10 numbers is 65. If one number is removed and 25 is included in the list. The new arithmetic mean is 60. The removed number is

  1. A. 75
  2. B. 65
  3. C. 60
  4. D. 80

Answer: Option A

Explanation:

Original sum = 10 × 65 = 650. New sum = 10 × 60 = 600. 650 − x + 25 = 600 → x = 75.

68.

The area of a square shaped plot is 3600 sq.ft. If the lengths of all the sides of the plot are doubled, then the area of the plot is

  1. A. 14600 sq.ft
  2. B. 14800 sq.ft
  3. C. 12200 sq.ft
  4. D. 14400 sq.ft

Answer: Option D

Explanation:

Side = √3600 = 60 ft. Doubled side = 120 ft. Area = 120² = 14400 sq.ft (4 times the original).

69.

A sum of rupees fetches simple interest Rs.2400 for 2 years. If the rate of interest is 12%, then the principal amount is

  1. A. Rs.12000
  2. B. Rs.10000.
  3. C. Rs.8000
  4. D. Rs.10200

Answer: Option B

Explanation:

SI = P × R × T ÷ 100 → 2400 = P × 12 × 2 ÷ 100 → P = Rs. 10000.

70.

A has deposited some amount in a bank. The bank gives 10% compound interest. If he receives Rs.24200 at the end of two years, the amount deposited initially in the bank is

  1. A. Rs.21000
  2. B. Rs.20000
  3. C. Rs.22000
  4. D. Rs.22200

Answer: Option B

Explanation:

Amount = P × (1.1)² = 1.21P. 1.21P = 24200 → P = Rs. 20000.

71.

The ratio of four numbers is 3 : 4 : 5 : 6 and the sum of the four numbers is 7200. The largest of the four numbers, is

  1. A. 2800
  2. B. 2600
  3. C. 3200
  4. D. 2400

Answer: Option D

Explanation:

3 + 4 + 5 + 6 = 18 parts = 7200, so 1 part = 400. Largest = 6 × 400 = 2400.

72.

Choose the prime number from 175, 161, 129, 101

  1. A. 161
  2. B. 101
  3. C. 175
  4. D. 129

Answer: Option B

Explanation:

175 = 5² × 7, 161 = 7 × 23, 129 = 3 × 43. 101 has no factor other than 1 and itself, so it is prime.

73.

If a : b = 4 : 5, b : c = 5 : 4 and c : d = 6 : 5, then a : b : c : d =

  1. A. 12 : 16 : 12 : 10
  2. B. 10 : 15 : 10 : 12
  3. C. 12 : 15 : 12 : 10
  4. D. 12 : 15 : 10 : 12

Answer: Option C

Explanation:

a : b : c = 4 : 5 : 4. Make c = 12 → a : b : c = 12 : 15 : 12. c : d = 6 : 5 = 12 : 10. So a : b : c : d = 12 : 15 : 12 : 10.